

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
1401. |
What did historian Gareth Stedman Jones say about the ‘City of London ? |
Answer» (i) London was a city of clerks and shopkeepers. (ii) It was a city of small masters and skilled artisans. (iii) It was a city of growing number of semi skilled and sweated out workers, of soldiers and servants, of casual labourers, street sellers and beggars. (iv) Apart from the London dockyards, five major types of industries that employed large number of people were : Clothing and footwear, wood and furniture, metals and engineering, printing and stationery and precision products such as surgical instruments, watches and objects of precious metal. (v) During the Fire World War. London began manufacturing motor care and electrical goods and the number of large factories increased until they accounted for nearly one- third of all jobs in the city. |
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1402. |
What were the changes in the kind of work available to women in London between the nineteenth and the twentieth century? Explain the factors which led to this change. |
Answer» twentieth century were primarily based on industrial and technological advancements. Consequently, women had to work in households for a living, and this led to an increase in the number of domestic servants. Some women also began to earn by lodging out rooms, tailoring, washing or making matchboxes. With the coming of the First World War though, women once again joined the industrial sector. |
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1403. |
A mass of 10 gm moving with a velocity of 100 cm / s strikes a pendulum bob of mass 10 gm . The two masses stick together. The maximum height reached by the system now is `(g=10m//s^(2))`A. zeroB. 5 cmC. 2.5 cmD. 1.25 cm |
Answer» Correct Answer - D |
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1404. |
A completely inelastic collision is one in which the two colliding particlesA. Are separated after collisionB. Remain together after collisionC. Split into small fragments flying in all directionsD. None of the above |
Answer» Correct Answer - B |
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1405. |
In an inelastic collision, what is conseved.A. Kinetic energyB. MomentumC. Both (a) and (b)D. neither (a) nor (b) |
Answer» Correct Answer - B |
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1406. |
A neutron travelling with a velocity `v` and kinetic energy `E` collides perfectly elastically head on with the nucleus of an atom of mass number `A` at rest. The fraction of the total kinetic energy retained by the neutron isA. `((A-1)/(A+1))^(2)`B. `((A+1)/(A-1))^(2)`C. `((A-1)/(A))^(2)`D. `((A+1)/(A))^(2)` |
Answer» Correct Answer - A |
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1407. |
A sphere collides with another sphere of identical mass. After collision, the two spheres move. The collision is inelastic. Then the angle between the directions of the two spheres isA. `90^(@)`B. `0^(@)`C. `45^(@)`D. Different from `90^(@)` |
Answer» Correct Answer - D |
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1408. |
A body of mass `4 kg` moving with velocity `12 m//s` collides with another body of mass `6 kg` at rest. If two bodies stick together after collision , then the loss of kinetic energy of system isA. zeroB. 288 jC. 172.8 jD. 144 j |
Answer» Correct Answer - C |
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1409. |
A smooth sphere of mass M moving with velocity u directly collides elastically with another sphere of mass m at rest. After collision their final velocities are V and v respectively. The value of v isA. `(2uM)/(m)`B. `(2um)/(M)`C. `(2u)/(1+(m)/(M))`D. `(2u)/(1+(M)/(m))` |
Answer» Correct Answer - C |
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1410. |
An object of mass 6 kg falls from a height of 5 m. Find the change in its potential energy. (g = 10 m/s2) |
Answer» When the object falls its potential energy becomes zero when it reaches at ground level. So, change in potential energy is equal to potential energy when the object is at full height as in question. Mass = 6 kg, h = 5 m PE = mgh = 6 kg x 10 ms-2 x 5 ms = 300 J |
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1411. |
A machine moves an object of 40 kg mass to 10 m height. Find the amount of work done. |
Answer» Here mass = 40 kg, h = 10 m and g = 9.8 m/s2 Work done can be calculated as follows: W = F.s = mgh W = 40 kg x 9.8 ms-2 x 10 m = 3920 J = 3.92 kJ |
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1412. |
An object of mass m is at height h. What is its potential energy?(a) mgh(b) mg/h(c) mh/g(d) 1/2 mgh2 |
Answer» Correct answer is (a) mgh |
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1413. |
An object of mass m is moving with velocity y. What is the value of kinetic energy?(a) mv(b) mgv(c) mv2(d) 1/2 mv2 |
Answer» Correct answer is (d) 1/2 mv2 |
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1414. |
Explain different types of dissipation of energy during conversion of energy. What can be done to reduce such dissipation? |
Answer» During conversion of energy from one form to another, all of energy does not get converted into one form of energy rather some of the energy is dissipated in the form of heat, light and sound energy. For example; when a ceiling fan is switched on, electrical energy is converted into kinetic energy. During this change, some of the energy is converted into heat energy which is evident from ceiling fan becoming hot. Following steps can be taken to reduce dissipation of energy:
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1415. |
What is electric energy? How is electricity produced in following: (a) Hydel electric plant (b) Wind energy plant (c) Solar energy plant |
Answer» (a) The energy in charged particles is called electrical energy. Flow of water is used for moving the turbine. Turbine converts kinetic energy into electric energy. (b) Blades of windmill move due to wind speed. Fan of windmill is attached to a turbine. Turbine converts kinetic energy into electric energy. (c) Solar energy plant uses two methods to produce electricity. In one method, photovoltaic cells convert heat energy into electric energy. In another method, water is converted into steam by using heat energy. Steam is then utilized to turn the turbines and electricity is produced. |
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1416. |
Which method is used to produce electricity in thermal power plant? (a) By heating chargeable cells (b) By boiling water to produce steam (c) By pushing pistons by heat energy (d) Any of the above |
Answer» (b) By boiling water to produce steam |
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1417. |
What is a solar cell panel? Write two advantages associated with such panels. |
Answer» It is a panel on which many solar cells are installed, which convert Sun’s energy into electrical energy. Two advantages: Solar cell panels can be setup at remote places and secondly it has no moving parts, require less maintenance and work quite satisfactorily without the use of any focusing device. |
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1418. |
Which method is used to produce electricity in hydro electric power plant? (a) By boiling the water to produce steam (b) By ionizing water (c) By running dynamo by kinetic energy of water(d) Any of the above |
Answer» (c) By running dynamo by kinetic energy of water |
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1419. |
How is electricity produced in hydel power plant? |
Answer» In hydel power plant, water is stored behind a dam. After that, water is released thorough sluice gates. The flow of water facilitated the movement in turbine. While doing so, kinetic energy of turbine is converted into electric energy. |
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1420. |
What do you understand by electrical energy? How is electricity obtained from thermal power plant? |
Answer» The energy in a charged object is called electric energy. In a thermal power plant, fuel is burnt to convert water into steam. The steam is then channelized to propellers of turbine, The flow of steam facilitates the movement in turbine. While doing so, kinetic energy of turbine is converted into electric energy. |
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1421. |
Explain the working of a hydroelectric power plant to produce electricity. |
Answer» In order to produce hydroelectricity, high rise dams are constructed on the river to obstruct the flow of water and thereby collect water in very large reservoirs. The water from high level in the dam is carried through pipes, to the turbine, at the bottom of the dam. The turbines are connected to the generator. Rotation of the turbines makes the generator produce electricity. Water when stored at a height in the dam has a large amount of potential energy which gets converted into the kinetic energy of flowing water when it is allowed to fall on the turbines it gets converted into mechanical energy of the turbine and finally gets converted into the electric energy by the generator. |
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1422. |
What is the work done by earth’s gravitational force in keeping the moon in its orbit in a complete revolution? |
Answer» Zero, because gravitational force is a conservative force and act perpendicular to direction of motion of moon. |
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1423. |
What is the work done by earth’s gravitational force in keeping the moon in its orbit? |
Answer» Work done is zero since force and displacement are in perpendicular direction, i.e. w = 0. |
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1424. |
A bomb of mass `30 kg` at rest explodes into two pieces of mass `18 kg` and `12 kg`. The velocity of mass `18 kg is 6 m//s`. The kinetic energy of the other mass isA. 256 JB. 486 JC. 524 JD. 324 J |
Answer» Correct Answer - B |
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1425. |
A bomb of mass 3 m kg explodes into two pieces of mass m kg and m kg . If the velocity of m kg mass is 16 m / s , the total kinetic energy released in the explosion isA. 192 mJB. 96 mJC. 384 mJD. 768 mJ |
Answer» Correct Answer - A |
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1426. |
A bomb of 12 kg explodes into two pieces of masses 4 kg and 8 kg . The velocity of 8 kg mass is 6 m / sec . The kinetic energy of the other mass isA. 48 JB. 32 JC. 24 JD. 288 J |
Answer» Correct Answer - D |
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1427. |
A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s . The velocity of the heaviest fragment will beA. 11.5 m/sB. 14.0 m/sC. 7.0 m/sD. 9.89 m/s |
Answer» Correct Answer - D |
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1428. |
State and explain one example where (i) Kinetic energy is present in a body and is used; and (ii) Potential energy is present in a body and is used. |
Answer» (i) Kinetic energy is the energy present in a body by virtue of its motion. When water is stored in a dam at particular height, we say it has maximum potential energy as the water is present at a height. When this water is allowed to fall down from a certain height, it is said to have kinetic energy. When the water falls on a turbine, the paddle wheels rotates to rotate the turbine. Hence the kinetic energy of water is used to push or rotate the turbine which is further used to produce the electricity. (ii) Potential energy present in a body is due to virtue of its position. In hydel power plant, the kinetic energy of water to rotate the turbine is obtained by the use of potential energy of water stored in dam. When water is stored in dam at a certain height, potential energy is stored in the water which transforms into kinetic energy when it released from that height. |
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1429. |
Explain the following: (a) An object increases its potential energy when raised through a height. (b) Energy is neither created nor destroyed then from where do we get energy. (c) When we push the wall, the wall does not move and no work is done. |
Answer» (a) An object has some mass ‘M, when it is raised through a certain height, energy is applied on it, this energy gets transformed and is gained by the object hence its potential energy increases. (b) Energy is present in every object in some or other form. It exist in sun, planet, wind, water etc, the energy gets transformed and we get, because of its transformation into different form. For e.g., sun energy → plants convert it (due to chemical reaction) into food energy → we eat green vegetables products of plants, energy enters our body (c) Work is said to be done, when force is applied on the body and it moves to certain distance. When a wall is pushed there is no displacement and we say that work done is zero. |
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1430. |
A bomb is kept stationary at a point. It suddenly explodes into two fragments of masses 1 g and 3 g. the total K.E. of the gragments is `6.4xx10^(4)J`. What is the K.E. of the smaller fragmentA. `2.5xx10^(4)J`B. `3.5xx10^4J`C. `4.8xx10^(4)J`D. `5.2xx10^(4)J` |
Answer» Correct Answer - C |
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1431. |
A particle of mass 4 m which is at rest explodes into three fragments. Two of the fragments each of mass m are found to move with a speed v each in mutually perpendicular directions. The total energy released in the process of explosion is ............A. `m upsilon^(20`B. `(3)/(2)m upsilon^(2)`C. `2 m upsilon^(2)`D. `4 m upsilon^(2)` |
Answer» Correct Answer - B Here,`m_(1)=m_(2)=m, m_(3)=4m-2m=2m,` `p_(1)=p_(2)=m upsilon` . A these pieces move perpendicular to each other, their resultant momentum `=p=sqrt(p_(1)^(2)+p_(2)^(2))=sqrt((m upsilon)^(2)+( m upsilon)^(2))=m upsilonsqrt(2)` Principle of conservation of linear momentum gives `p_(3)=m_(3) upsilon_(3) =p= m upsilonsqrt(2)` `upsilon_(3)=( m upsilon sqrt(2))/( m_(3))=( m upsilonsqrt(2))/( 2m)=(upsilon)/( sqrt(2))` Total `K.E.=(1)/(2) m _(1)upsilon_(1)^(2)+(1)/(2)m_(2)upsilon_(2)^(2)+(1)/(2) m_(3)upsilon_(3)^(2)` `=(1)/(2) m upsilon^(2)+ (1)/(2) m upsilon^(2) +(1)/(2) (2m) ((upsilon)/(sqrt(2)))^(2)` `E=(3)/(2) m upsilon^(2)` |
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1432. |
Force on a body 1 exerted by body 2 is equal to that on body 2 by body 1. Is it necessary that work done on 1 by 2 is equal and opposite to work done on by 1? |
Answer» No. A car exerts some force on the road and road exerts same force on the car but displacement of road is zero so work done by road is zero. |
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1433. |
Convert 1 kWh into joules. |
Answer» 1 kWh = 1 kW x 1 h = 1000 W x 3600 s = 3600000J = 3.6 x 106J |
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1434. |
A bomb at rest explodes into two fragments of masses `3.0kg` and `1.0kg`. The total kinetic energy of the fragments is `6xx10^(4)J`. Calculate (i) , kinetic energy of the bigger fragment (ii) momentum of the smaller fragment. |
Answer» If `upsilon_(1), upsilon_(2)` are velocities of fragments of masses `m_(1)=3kg` and `m_(2)=1kg`, then according to the principle of conservation of linear momentum, `m_(1)upsilon_(1)+m_(2)upsilon_(2)` `3upsilon_(2)+1upsilon_(2)=0` or ` (upsilon_(1))/(upsilon_(2))=-(1)/(3)` `(E_(1))/(E_(2))=((1)/(2)m_(1)upsilon_(1)^(2))/((1)/(2)m_(2)upsilon_(2)^(2))=(3)/(1)(-(1)/(3))^(2)=(1)/(3)` As total `K.E.=E=E_(1)+E_(2)=6xx10^(4)J` `:. E_(1)=(6xx10^(4)xx1)/((1+3))=1.5xx10^(4)J` `E_(2)=6xx10^(4)-1.5xx10^(4)=4.5xx10^(4)J` Linear momentum of smaller fragment `P_(2)=sqrt(2mE_(2))=sqrt(2xx1xx4.5xx10^(4))` `3xx10^(2)kg ms^(-1)` As the direction is opposite `:. P_(2)=-300kg ms^(-1)` |
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1435. |
Convert 1 kWh in joule. |
Answer» 1 kWh = 1000 × 3600 Ws = 3.6 × 106 J. |
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1436. |
kWh is the practical unit of (a) energy (b) power (c) electrical energy (d) none |
Answer» Correct answer is (a) energy |
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1437. |
A bomb of mass `16 kg ` at rest explodes into two pieces of masses `4kg` and `12kg`. If KE of `4 kg` mass is `288 J`, what is the velocity (in `ms^(-1)` of the other piece of `12 kg` ? |
Answer» Here, `m_(1)=4 kg, m_(2)=12 kg ` `E_(1)=(1)/(2) m_(1)upsilon_(1)^(2)` `288=(1)/(2) xx4 upsilon_(1)^(2), upsilon_(1)=sqrt((288)/( 2))=12 m//s` According to principle of conservation of linear momentum, `m_(1)upsilon_(1)+m_(2)upsilon_(2)=0` `upsilon_(2)=(-m_(1)upsilon_(1))/( m_(2))`, `upsilon_(2)=(-4xx12)/( 12)`=-4 m//s` |
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1438. |
Explain how the definition of work in physics is different from general perception. |
Answer» The term work is used in diverse contexts in daily life. It refers to both physical as well as mental work. In fact, any activity can generally be called as work. But in Physics, the.term work is treated as a physical quantity with a precise definition. Work is said to be done by the force when the force applied on a body displaces it. |
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1439. |
A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then, the long piece will have a force constant of(a) \(\frac{2}{3} k\)(b) \(\frac{3}{2}k\)(c) \(3k\)(d) 6\(k\) |
Answer» Correct answer is (b) \(\frac{3}{2} k\) |
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1440. |
Auto manufactures study the collision of cars with mounted spring of different spring constant. Consider a car of mass 1500 kg moving with a speed of `36 kmh^(-1)` on a smooth road and colliding with a horizontally mounted spring of spring constant `7.5xx10^(3) Nm^(-1)`. Find the maximum compression of the spring . |
Answer» At maximum compression, KE of car gets converted completely into PE of the spring. `KE " of " car =K=(1)/(2)mv^(2)=(1)/(2)xx1500xx10xx10` `(v=36xx(5)/(18)=10 ms^(-1))` `=7.5xx10^(4) J` At maximum compression `x_(m)`, PE,U of the spring =KE, K of car `U=(1)/(2)kx_(m)^(2)=7.5xx10^(4) Jimpliesx_(m)=sqrt((2xx7.5xx10^(4))/(7.5xx10^(3)))=4.47 m` |
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1441. |
To simulate car accidents, auto manufacturers study the collisions of moving cars with mounted springs of different spring constants. Consider a typical simulation with a car of mass 1000 kg moving with a speed 18.0 kmh-1 on a smooth road and colliding with a horizontally mounted spring of spring constant 6.25 × 10-3 Nm-1 . What is the maximum compression of the spring? |
Answer» At maximum compression xm , the K.E. of the car is converted entirely into the P.E. of the spring. ∴ \(\frac{1}{2} kx^2_m\) = \(\frac{1}{2} mv^2\) or \(x_m\) = 2m. |
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1442. |
Does the P.E. of a spring decreases or increases when it is compressed or stretched? |
Answer» Increases because W.D. on it when it increases is compressed or stretched. |
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1443. |
A spring of force constant K is cut into two equal pieces. Calculate force constant of each part. |
Answer» Force constant of each half becomes twice the force constant of the original spring. |
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1444. |
Define spring constant of a spring. |
Answer» It is the restoring force set up in a string per unit extension. |
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1445. |
A mass m collides with the other mass m and sticks to it. What Is the nature of collision? |
Answer» Whenever a mass collides and sticks to other mass, the nature of collision is inelastic. |
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1446. |
A spherical ball of mass `20kg` is stationary at the top of a hill of height `100m` , it rolls down a smooth surface to the ground , then climbs up another bill of height of `30 m` and final rolls down to a horizontal base at a height of `20 m` about the ground . The velocity attained by the ball isA. 10 m/sB. `10sqrt(30)m//s`C. `40m//s`D. `20m//s` |
Answer» Correct Answer - C |
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1447. |
A spherical ball of mass `20kg` is stationary at the top of a hill of height `100m` , it rolls down a smooth surface to the ground , then climbs up another bill of height of `30 m` and final rolls down to a horizontal base at a height of `20 m` about the ground . The velocity attained by the ball is |
Answer» According to conservation of energy. `mgH=(1)/(2) mv^(2)+mgh_(2)impliesmg(H-h_(2))=(1)/(2)mv^(2)` where, H=height of the first hill, `h_(1)`=height of the second hill `h_(2)`= height of the horizontal base v=velocity attained by the ball `implies v=sqrt(2g(100-20))=sqrt(2xx10xx80)=40 ms^(-1)` |
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1448. |
20 J work is required to stretch a spring through 0.1m. Find the force constant of the spring. If the spring is further stretched through 0.1 m, calculate work done. |
Answer» P.E. of spring when stretched through a distance 01m, U = W.D = \(\frac{1}{2}\)Kx2 = 20J K = 4000 N/m when spring is further stretched through 01m, then P.E. will be : U' = \(\frac{1}{2}\) K(0.2)2 = 80J ∴ W.D = U' -U = 80-20 = 60J. |
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1449. |
If the angle between force and displacement is obtuse, then the work done is (a) positive (b) negative(c) zero (d) minimum |
Answer» (b) negative |
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1450. |
1 erg is equivalent to (a) 10-7 J (b) 1.6 × 10-19 J (c) 4.186 J (d) 3.6 × 10-6 J |
Answer» Correct answer is (a) 10-7 J |
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