1.

1). 13/182). 65/763). 31/384). 13/15

Answer»

There are total 20 people in the party.

∴ Total number of possible shake HANDS = 20c2 = 190

Number of ways where an woman shakes hand with her HUSBAND = 10 [There are 10 women]

Number of ways where Indian women shakes hand with AMERICAN MAN = 5 × 5 = 25

∴ Total number of ways where no wife shakes hand with her own husband and no Indian woman shakes hand with an American man = (190 – 25 – 10) = 155

⇒ Required probability = (155/190) = 31/38



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