InterviewSolution
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1). 13/182). 65/763). 31/384). 13/15 |
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Answer» There are total 20 people in the party. ∴ Total number of possible shake HANDS = 20c2 = 190 Number of ways where an woman shakes hand with her HUSBAND = 10 [There are 10 women] Number of ways where Indian women shakes hand with AMERICAN MAN = 5 × 5 = 25 ∴ Total number of ways where no wife shakes hand with her own husband and no Indian woman shakes hand with an American man = (190 – 25 – 10) = 155 ⇒ Required probability = (155/190) = 31/38 |
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