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Cards numbered from 1 to 33 are put in a bag. A card is drawn from it at random. Find the probability that the number on the card is not divisible by 3 but divisible by 5?1). \(\frac{1}{{11}}\)2). \(\frac{5}{{33}}\)3). \(\frac{4}{{33}}\)4). \(\frac{8}{{33}}\) |
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Answer» Numbers from 1 to 33 divisible by 5 = {5, 10, 15, 20, 25, 30} Numbers from 1 to 33, not divisible by 3 but divisible by 5 = {5, 10, 20, 25} Number of possible outcomes = 33 ∴ Probability = $(\FRAC{{n\left( {Favourable\;Events} \right)}}{{n\left( {Possible\;outcomes} \right)}}\; = \;\frac{4}{{33}})$ |
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