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Mayank threw two dice simultaneously. What is the probability of getting a total of 7?1). 1/62). 1/43). 2/34). 3/4 |
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Answer» On THROWING TWO DICE, n(S) = 6 × 6 = 36 Number of events of getting a total of 7, n(E) = 6, i.e. (1,6), (2,5) , (3,4), (4,3) , (5,2), (6,1) ∴ Probability of getting a total of 7 = n(E)/n(S) = (6/36) = (1/6) |
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