1.

A bag contains 4 red balls, 6 White balls, 8 Green balls and 10 Black balls. If one ball is drawn at random, find the probability that it is Black.1). 5/142). 5/163). 1/164). 4/15

Answer»

Let S be the sample space.

Then, total number of BALLS = (4 + 6 + 8 + 10) = 28 balls

Thus, N(S) = 28

Let E = event that the ball drawn is black

? There are 10 black balls in the bag

Thus, n(E) = 10

PROBABILITY of occurrence of event;

P(E) = n(E)/n(S) = 10/28 = 5/14


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