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A bag contains 4 red balls, 6 White balls, 8 Green balls and 10 Black balls. If one ball is drawn at random, find the probability that it is Black.1). 5/142). 5/163). 1/164). 4/15 |
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Answer» Let S be the sample space. Then, total number of BALLS = (4 + 6 + 8 + 10) = 28 balls Thus, N(S) = 28 Let E = event that the ball drawn is black ? There are 10 black balls in the bag Thus, n(E) = 10 ∴ PROBABILITY of occurrence of event; P(E) = n(E)/n(S) = 10/28 = 5/14 |
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