1.

Three coins are tossed simultaneously. What is the probability of getting at least two tails out of three?1). 1/22). 1/33). 2/34). 1/4

Answer»

⇒ Here, S = {(HHH), (HHT), (HTH), (HTT), (THH), (THT), (TTH), (TTT)}

⇒ n(S) = 23 = 8

⇒ Let event E = getting at least two tails

⇒ {(HTT), (THT), (TTH), (TTT)}}

∴ n(E) = 4

Now, probability of getting at least two tails

⇒ P(E) = n(E)/n(S) = 4/8 = 1/2


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