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9 sec2A − 9 tan2A is equal to A. 1 B. 9 C. 8 D. 0 |
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Answer» To find: 9 sec2A – 9 tan2A Consider 9 sec2A – 9 tan2A = 9 (sec2A – tan2A) ∵ 1 + tan2A = sec2A ∴ 9 sec2A – 9 tan2A = 9 (sec2A – tan2A) = 9 (1 + tan2A – tan2A) = 9 |
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