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Prove the following trigonometric identities:\(\frac{1-cosθ}{sinθ}=\frac{sinθ}{1+cosθ}\) |
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Answer» \(\frac{1-cosθ}{sinθ}=\frac{1-cosθ}{sinθ}\times\frac{1+cosθ}{1+cosθ}\) = \(\frac{1-cos^2θ}{sinθ(1+cosθ)}\) = \(\frac{sin^2θ}{sinθ(1+cosθ)}\) = \(\frac{sinθ}{1+cosθ}\) Hence Proved. |
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