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In a right ∆ABC , right-angled at B, if tan A = 1 , then verify that 2 sin A·cos A = 1. |
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Answer» Consider ΔABC to be a right angled triangle at B. angle C = 90 degree Given: tan A = 1 …(1) tan A = 1 = BC/AB AB = BC Again, tan A = sin A/cos A sin A = cos A …using (1) By Pythagoras theorem: AC2 = BC2 + AB2 AC2 = 2BC2 (AC/BC)2 = 2 Or AC/BC = √2 cosec A = √2 or sin A = 1/√2 and cos A = 1/√2 Now, 2 sin A cos A = 2(1/√2)( 1/√2) = 2(1/2) = 1 = RHS |
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