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A 12 MHz clock frequency is applied to a cascaded counter containing a modulus-5 counter, a modulus-8 counter, and a modulus-10 counter. The lowest output frequency possible is ________(a) 10 kHz(b) 20 kHz(c) 30 kHz(d) 60 kHzThe question was posed to me by my school principal while I was bunking the class.My doubt is from Counter ICs in section Counters of Digital Circuits

Answer»

Right option is (c) 30 kHz

To elaborate: Cascaded COUNTER containing a modulus-5 counter, a modulus-8 counter, and a modulus-10 counter. So, 5*8*10=400. Applied clock frequency = 12 MHz; HENCE, the LOWEST output frequency POSSIBLE is 12MHz/400=30 kHz.



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