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A bidirectional 4-bit shift register is storing the nibble 1101. Its input is HIGH. The nibble 1011 is waiting to be entered on the serial data-input line. After three clock pulses, the shift register is storing ________(a) 1101(b) 0111(c) 0001(d) 1110I had been asked this question by my college professor while I was bunking the class.My question is taken from Universal Shift Registers topic in section Registers of Digital Circuits

Answer»

Correct option is (b) 0111

Easiest explanation: Mode is high MEANS it’s a right shift REGISTER. Then after 3 clock pulses enter bits are 011 and remained bit in register is 1. Therefore, 0111 is the required solution.

1011 | 1101

101 | 1110-> 1^st clock PULSE

10 | 1111-> 2^ndclock pulse

1 | 0111-> 3^rd clock pulse.



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