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A box contains 2 blue caps, 4 red caps, 5 green caps and 1 yellow cap. If one cap is picked at random, what is the probability that it is either blue or yellow?1). 2/92). 1/43). 3/84). 6/11 |
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Answer» <P>Total number of caps in box = (2 blue + 4 red + 5 green + 1 yellow) caps = 12 Let, E1 = event of picking a blue cap E2 = event of picking a yellow cap Then, P(E1 ) = 2/12 P(E2) = 1/12 ∴ PROBABILITY of picking a cap that it is either blue or yellow = 2/12 + 1/12 = 3/12 = ¼ |
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