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A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

Answer» Volume of the large cube = (33 + 43 + 53) = 216 cm3. Let the edge of the large cube be a. So, a3 = 216         a = 6 cm. Required ratio = 6 x (32 + 42 + 52) = 50 = 25 : 18. 6 x 62 36


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