A particle of mass m starts from the mean position of a SHM, at t=0, and goes towards -A. If the angular frequency of SHM is w, find the force acting on it as a function of time.(a) mAw^2sin(wt)(b) mAw^2sin(wt+π)(c) -mAw^2cos(wt+π)(d) -mAw^2cos(wt)I had been asked this question during an online exam.This key question is from Oscillations topic in section Oscillations of Physics – Class 11

A particle of mass m starts from the mean position of a SHM, at t=0, a

1.	A particle of mass m starts from the mean position of a SHM, at t=0, and goes towards -A. If the angular frequency of SHM is w, find the force acting on it as a function of time.(a) mAw^2sin(wt)(b) mAw^2sin(wt+π)(c) -mAw^2cos(wt+π)(d) -mAw^2cos(wt)I had been asked this question during an online exam.This key question is from Oscillations topic in section Oscillations of Physics – Class 11
Answer» RIGHT OPTION is (a) mAw^2sin(wt) The explanation is: The displacement equation will be given by: x = -Asin(wt).On taking its DERIVATIVE, we GET:v = -Awcos(wt).Further, we get: a = Aw^2sin(wt).Thus, force is given by: F(t) = mAw^2sin(wt).

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