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Let T1 be the time period of a single spring mass system on a horizontal surface. Let T2 be the time period of the same system when hung from the ceiling. What is the expression for T1 & T2?(a) T1 = T2 = 2π √(k/m)(b) T1 = 2π √(m/k), T2 = 2π √(mg/k)(c) T1 = T2 = 2π √(m/k)(d) T1 = 2π √(m/k), T2 = 2π √(k/mg)This question was posed to me in an interview for job.This key question is from Oscillations in division Oscillations of Physics – Class 11 |
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Answer» The correct option is (c) T1 = T2 = 2π √(m/k) |
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