1.

Consider a particle undergoing an SHM of amplitude A & angular frequency w. What is the magnitude of displacement from the mean position when kinetic energy is equal to the magnitude of potential energy?(a) A/2(b) A/√2(c) A/3(d) A/4This question was addressed to me by my college director while I was bunking the class.My question is from Oscillations topic in chapter Oscillations of Physics – Class 11

Answer»

Right CHOICE is (b) A/√2

To EXPLAIN: Let x = Asin(wt).

∴ Kinetic ENERGY = 1/2 mA^2w^2cos^2(wt)

potential energy = 1/2kA^2sin^2(wt).

According to given condition:

1/2mA^2w^2cos^2(wt) = 1/2A^2w^2sin^2(wt)USING, k = mw^2, we get:tan^2(wt) = 1.

∴ wt = π/4.∴ x = Asin(π/4) = A/√2.


Discussion

No Comment Found

Related InterviewSolutions