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Cards numbered from 153 to 199 are put in a bag. A card is drawn from it at random. Find the probability that the number on the card is not divisible by both 11 and 13?1). \(\frac{{38}}{{47}}\)2). \(\frac{9}{{47}}\)3). 14). 0 |
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Answer» Number of possible OUTCOMES = n(S) = 47 Number of favourable outcomes = 47[No number is divisible BYBOTH 11 and 13 in between 153 and 199] ∴ Required probability = 1 |
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