1.

Cards numbered from 5 to 55 are put in a bag. A card is drawn from it at random. Find the probability that the number on the card is not divisible by 3 but divisible by 7?1). \(\frac{7}{{50}}\)2). \(\frac{1}{{10}}\)3). \(\frac{5}{{51}}\)4). \(\frac{{19}}{{51}}\)

Answer»

Numbers from 5 to 55 divisible by 7 = {7, 14, 21, 28, 35, 42, 49}

Numbers from 5 to 55, not divisible by 3 but divisible by 7 = {7, 14, 28, 35, 49}

Number of total possible OUTCOMES = 51

∴ Probability = $(\frac{{n\left( {Favourable\;Events} \RIGHT)}}{{n\left( {Possible\;outcomes} \right)}}\; = \;\frac{5}{{51}})$


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