InterviewSolution
Saved Bookmarks
| 1. |
Differentiate 3x+ x3 + 4x − 5 with respect to x. |
|
Answer» Let, f(x) = 3x + x3 + 4x − 5 ∴ \(\frac{d}{dx}f(x)=\frac{d}{dx}f(x)\) ⟹ \(f'(x)=\frac{d}{dx}(3^x+x^3+4x-5)\) = 3x loge 3 + 3x2 + 4 ∙1 − 0 = 3x loge 3 + 3x2 + 4. |
|