1.

Differentiate 3x+ x3 + 4x − 5 with respect to x.

Answer»

Let, 

f(x) = 3x + x3 + 4x − 5

∴ \(\frac{d}{dx}f(x)=\frac{d}{dx}f(x)\)

⟹ \(f'(x)=\frac{d}{dx}(3^x+x^3+4x-5)\)

= 3x loge 3 + 3x2 + 4 ∙1 − 0

= 3x loge 3 + 3x2 + 4.



Discussion

No Comment Found