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Differentiate with respect to x : exsin x + xncos x |
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Answer» f(x) = ex sin x +xn cos x ∴ f'(x) = \(\frac{d}{dx}\){ex sin x + xn cos x} = \(\frac{d}{dx}\)(exsin x)+\(\frac{d}{dx}\)(xncos x) = sinx\(\frac{d}{dx}\)ex + ex\(\frac{d}{dx}\)sinx + cosx\(\frac{d}{dx}\)xn + xn\(\frac{d}{dx}\)cosx = sin.ex + ex . cos x + cos x ∙ nxn−1 + xn . (− sin x) = ex (sin x + cos x) + xn−1 [ncos x − xsin x] |
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