1.

Factorize `9z^3-27 z^2-100 z+300 ,`if it is given that `(3z+10)`is a factor of it.

Answer» `9z^3-27z^2-100z+300=(3z+10)(Az^2+bz+c)`
`=3AZ^3+3BZ^2+10AZ^2+3CZ+10NZ+10C`
`=3AZ^3+Z^2(3B+10A)+Z(3C+10B)+10C`
`3A=9`
`A=3`
`3B+10A=-27`
`B=-19`
`3C+10B=-100`
`10C=300`
`C=30`
`(3Z+10)(3Z^2-19Z+30)=0`
`3Z^2-9z-10z+30=0`
`3z(z-3)-10(z-3)=0`
`(3z-10)(z-3)=0`
`(3z+10)(3z-10)(z-3)`.


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