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    				| 1. | Factorize `9z^3-27 z^2-100 z+300 ,`if it is given that `(3z+10)`is a factor of it. | 
| Answer» `9z^3-27z^2-100z+300=(3z+10)(Az^2+bz+c)` `=3AZ^3+3BZ^2+10AZ^2+3CZ+10NZ+10C` `=3AZ^3+Z^2(3B+10A)+Z(3C+10B)+10C` `3A=9` `A=3` `3B+10A=-27` `B=-19` `3C+10B=-100` `10C=300` `C=30` `(3Z+10)(3Z^2-19Z+30)=0` `3Z^2-9z-10z+30=0` `3z(z-3)-10(z-3)=0` `(3z-10)(z-3)=0` `(3z+10)(3z-10)(z-3)`. | |