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Find the remainder when `f(x)=x^3-6x^2+2x-4`is divided by `g(x)=3x-1.` |
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Answer» When f(x) is divided by then remainder =f(a) `g(x)=3x-1=3(x-1/3)` `a=1/3` Rem`=f(1/3)=(1/3)^3-6(1/3)^2+2(1/3)-4` `=1/27-6/9+2/3-4` `=1/27-4` `=-107/27`. |
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