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    				| 1. | What must be added to `3x^3+x^2-22 x+9`so that the result is exactly divisible by `3x^2+7x-6?` | 
| Answer» `3x^3+x^2-22x+9=x(3x^2+7x-6)-2(3x^2+7x-6)-2x-3` `R=-2x-3` We need to add 2x+3. | |