1.

What must be added to `3x^3+x^2-22 x+9`so that the result is exactly divisible by `3x^2+7x-6?`

Answer» `3x^3+x^2-22x+9=x(3x^2+7x-6)-2(3x^2+7x-6)-2x-3`
`R=-2x-3`
We need to add 2x+3.


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