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    				| 1. | If `x=4/3`is a root of the polynomial `f(x)=6x^3-11 x^2+k x-20 ,`find the value of `k` | 
| Answer» x=a is root of f(x) f(a)=0 f(4/3)=0 `6*(4/3)^3-11(4/3)^2+k(4/3)-20=0` `6*64/27-11*16/9+4/3k-20=0` `(384-176*3+9*4k-20*27)/27=0` `384-528+36k-540=0` `36k=1068-384` `k=19`. | |