Find a and b ifa + 2b + 2ai = 4 + 6i

1.	Find a and b ifa + 2b + 2ai = 4 + 6i
Answer» a + 2b + 2ai = 4 + 6i Equating real and imaginary parts, we get a + 2b = 4 …..(i) 2a = 6 ……(ii) ∴ a = 3 Substituting, a = 3 in (i), we get 3 + 2b = 4 ∴ b = 1/2 ∴ a = 3 and b = 1/2 Check: For a = 3 and b = 1/2 Consider, L.H.S. = a + 2b + 2ai = 3 + 2(1/2) + 2(3)i = 4 + 6i = R.H.S.

Answer»

a + 2b + 2ai = 4 + 6i

Equating real and imaginary parts, we get

a + 2b = 4 …..(i)

2a = 6 ……(ii)

∴ a = 3

Substituting, a = 3 in (i), we get

3 + 2b = 4

∴ b = 1/2

∴ a = 3 and b = 1/2

Check:

For a = 3 and b = 1/2

Consider, L.H.S. = a + 2b + 2ai

= 3 + 2(1/2) + 2(3)i

= 4 + 6i

= R.H.S.

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