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Find the 7th term in the expansion of (3x2 – 1/x3)10. |
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Answer» Given as (3x2 – 1/x3)10 Lets consider the 7th term as T7 Therefore, T7 = T6+1 = 10C6 (3x2)10-6 (-1/x3)6 = 10C6 (3)4 (x)8 (1/x18) = [10 × 9 × 8 × 7 × 81] / [4 × 3 × 2 × x10] = 17010 / x10 ∴ The 7th term of the expression (3x2 – 1/x3)10 is 17010 / x10. |
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