1.

Find the 7th term in the expansion of (3x2 – 1/x3)10.

Answer»

Given as

(3x2 – 1/x3)10

Lets consider the 7th term as T7

Therefore,

T7 = T6+1

10C6 (3x2)10-6 (-1/x3)6

10C6 (3)4 (x)8 (1/x18)

= [10 × 9 × 8 × 7 × 81] / [4 × 3 × 2 × x10]

= 17010 / x10

∴ The 7th term of the expression (3x2 – 1/x3)10 is 17010 / x10.



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