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Find the 8th term in the expansion of (x3/2 y1/2 – x1/2 y3/2)10. |
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Answer» Given as (x3/2 y1/2 – x1/2 y3/2)10 Lets consider the 8th term as T8 Therefore, T8 = T7+1 = 10C7 (x3/2 y1/2)10-7 (-x1/2 y3/2)7 = -[10×9×8]/[3×2] x9/2 y3/2 (x7/2 y21/2) = -120 x8y12 ∴ The 8th term of the expression (x3/2 y1/2 – x1/2 y3/2)10 is -120 x8y12. |
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