1.

Find the 8th term in the expansion of (x3/2 y1/2 – x1/2 y3/2)10.

Answer»

Given as

(x3/2 y1/2 – x1/2 y3/2)10

Lets consider the 8th term as T8

Therefore,

T8 = T7+1

10C7 (x3/2 y1/2)10-7 (-x1/2 y3/2)7

= -[10×9×8]/[3×2] x9/2 y3/2 (x7/2 y21/2)

= -120 x8y12

∴ The 8th term of the expression (x3/2 y1/2 – x1/2 y3/2)10 is -120 x8y12.



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