InterviewSolution
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InterviewSolution
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Find the coefficient of x-2 in (x + \(\frac{1}{x^2}\))17 |
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Answer» Here, x → x, a → \(\frac{1}{x^2}\)and n = 17 ∴ Tr+1 = 17Cr.x17-r(\(\frac{1}{x^2}\))r Tr+1 = 17Cr.x17-r-2r = 17Crx17-3r To find the coefficient of x-2, equate the power of x to -2 17 – 3r = -2 ⇒ 17 + 2 = 3r ⇒ 3r ⇒ r = \(\frac{19}{3}\) Since r is a fraction the coefficient of x-2 is 0. |
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