1.

Find the coordinates of the foot of the perpendicular drawn from thepoint `(1,-2)`on the line `y=2x+1.`

Answer» Here, slope of line, `y = 2x+1` is `2`.
`:.` Slope of lineperpendicular to this line `= -1/2`
Let foot of the perpendicular is `(x_1,y_1)`.
Then, `y_1 = 2x_1+1.`
So, from the point, `(1,-2)`,
`(2x_1+1+2)/(x_1-1) = -1/2`
`=>(2x_1+3)/(x_1-1) = -1/2`
`=>4x_1+6 = 1-x_1`
`=>x_1 = -1`
`:. y_1 = 2(-1)+1 = -1`
So, foot of the perpenicular will be `(-1-1).`


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