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    				| 1. | Find the equation of the straight line which cuts off intercept onX-axis which is twice that on Y-axis and is at a unit distance from theorigin. | 
| Answer» Eqaution of a straight line can be given as, `x/a+y/b = 1` It is given that, `a = 2b` `:. x/(2b) +y/b = 1` Also, it is given that distance of this line from the origin is unit that is `1`. `:. |sqrt(1/b^2+1/(4b^2))| = 1` `=>1/b^2+1/(4b^2) = 1^2` `=>5 = 4b^2` `=>b = +-sqrt5/2` Putting value of `b` in equation of the line, `x/sqrt5+(2y)/sqrt5 = 1 and -x/sqrt5-(2y)/sqrt5 = 1` are the required equations. | |