1.

Find the equation of the straight line which cuts off intercept onX-axis which is twice that on Y-axis and is at a unit distance from theorigin.

Answer» Eqaution of a straight line can be given as,
`x/a+y/b = 1`
It is given that, `a = 2b`
`:. x/(2b) +y/b = 1`
Also, it is given that distance of this line from the origin is unit that is `1`.
`:. |sqrt(1/b^2+1/(4b^2))| = 1`
`=>1/b^2+1/(4b^2) = 1^2`
`=>5 = 4b^2`
`=>b = +-sqrt5/2`
Putting value of `b` in equation of the line,
`x/sqrt5+(2y)/sqrt5 = 1 and -x/sqrt5-(2y)/sqrt5 = 1` are the required equations.


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