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    				| 1. | Find the value of `m`for which the lines `m x+(2m+3)y+m+6=0a n dm x+(2m+1)x+(m-6)y+9=0`intersect at a; point on `y-a xi sdot` | 
| Answer» `(0,(-m+6)/(2m+3))` `(2m+3)y=-(m+6)` `y=(-m+6)/(2m+3)` `(m-6)y=-9` `y=(-9)/(m-6)` Point`(0,(-9)/(m-6))` `(m+6)/(2m+3)=9/(m-6)` `m^2-36=18m+27` `m^2-18m-63=0` `m^2-21m+3m-63=0` `m(m-21)+3(m-21)=0` `(m+3)(m-21)=0` `m=21,-3`. | |