1.

Find the value of `m`for which the lines `m x+(2m+3)y+m+6=0a n dm x+(2m+1)x+(m-6)y+9=0`intersect at a; point on `y-a xi sdot`

Answer» `(0,(-m+6)/(2m+3))`
`(2m+3)y=-(m+6)`
`y=(-m+6)/(2m+3)`
`(m-6)y=-9`
`y=(-9)/(m-6)`
Point`(0,(-9)/(m-6))`
`(m+6)/(2m+3)=9/(m-6)`
`m^2-36=18m+27`
`m^2-18m-63=0`
`m^2-21m+3m-63=0`
`m(m-21)+3(m-21)=0`
`(m+3)(m-21)=0`
`m=21,-3`.


Discussion

No Comment Found