1.

Find the equation of a straight line which makes an angle of `tan^(-1)sqrt(2)`with the x-axisand cuts off an intercept of `=3/(sqrt(2))`with the y-axis

Answer» Equation of a straight line can be given as,
`y = mx+c`
Here, `y-` intercept `(c)= 3/sqrt2`
`theta = tan^-1(sqrt2)`
`=>tantheta = sqrt2`
`:. m = tan theta = sqrt2`
`:.` Equation of the line,
`y = sqrt2x+3/sqrt2`
`=>2x - sqrt2y +3 =0.`


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