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Find the equation of a straight line which makes an angle of `tan^(-1)sqrt(2)`with the x-axisand cuts off an intercept of `=3/(sqrt(2))`with the y-axis |
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Answer» Equation of a straight line can be given as, `y = mx+c` Here, `y-` intercept `(c)= 3/sqrt2` `theta = tan^-1(sqrt2)` `=>tantheta = sqrt2` `:. m = tan theta = sqrt2` `:.` Equation of the line, `y = sqrt2x+3/sqrt2` `=>2x - sqrt2y +3 =0.` |
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