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Find the equation in cartesian coordinates of the locus of z if |z - 3| = 2 |
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Answer» Let z = x + iy |z – 3| = 2 |x + iy – 3| = 2 |(x – 3) + iy| = 2 \(\sqrt{(x-3)^2+y^2}=2\) \(\therefore\) (x - 3)2 + y2 = 4 |
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