1.

Find the equation in cartesian coordinates of the locus of z if |z - 3| = 2

Answer»

Let z = x + iy

|z – 3| = 2

|x + iy – 3| = 2

|(x – 3) + iy| = 2

\(\sqrt{(x-3)^2+y^2}=2\) 

\(\therefore\) (x - 3)2 + y2 = 4



Discussion

No Comment Found