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Find the harmonic mean of the roots of the equation (5+√2)\(x\)2 - (4 + √5)\(x\) + (8+2√5) = 0. |
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Answer» Let the roots of the equation be α and β. Then, Sum of roots = α + β = \(\frac{(4+\sqrt5)}{5+\sqrt2}\) Product of roots = αβ = \(\frac{8+2\sqrt5}{5+\sqrt2}\) Now, Harmonic Mean of the roots, α and β = \(\frac{2\alpha\beta}{\alpha+\beta}\) = \(\frac{2\bigg(\frac{8+2\sqrt5}{5+\sqrt2}\bigg)}{\frac{(4+\sqrt5)}{5+\sqrt2}}\) = \(\frac{4(4+\sqrt5)}{4+\sqrt5}\) = 4. |
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