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Find the value of 30C1 + 30C2 + 30C3 +… + 30C30 . |
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Answer» (1 + x)n = nC0 + nC1x+nC2x2+ nC3x3+ …. Putting x = 1 (1 + 1)n = nC0 + nC1 +nC2 + nC3 + …. + nCn or 2n = nC0 + nC1 +nC2 + nC3 + …. + nCn Here, putting n = 30. 230 = 1+ 30C1 +30C2 + 30C3 + …. + 30C3o ⇒ 1+ 30C1 +30C2 + 30C3 + …. + 30C3o = 230 ⇒ 30C1 + 30C2 + 30C3 + … + 30c30 = 230 – 1 |
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