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Find the value of cos 135°.(a) \(\frac {1}{\sqrt {2}}\)(b) √2(c) -√2(d) \(\frac {-1}{\sqrt {2}}\)This question was addressed to me during a job interview.The query is from Trigonometric Ratios of Complementary Angles in division Trigonometry of Mathematics – Class 10

Answer» CORRECT option is (d) \(\frac {-1}{\SQRT {2}}\)

Explanation: COS 135° = Cos (90° + 45°)

= -Sin 45°

= \(\frac {-1}{\sqrt {2}}\)


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