1.

Find the value of following expression: i49 + i68 + i89 + i110

Answer»

i49 + i68 + i89 + i110 = i(48 + 1) + i68 + i(88 + 1) + i(108 + 2) 

= (i4)12 × i + (i4)17 + (i4)11 × i + (i4)27 × i2

= i + 1 + i – 1 = 2i 

[since i4 = 1, i2 = – 1] 

i49 + i68 + i89 + i110 = 2i



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