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Force on a particle is given by: F = -kx^n. For what values of n will the motion be oscillatory?(a) 3(b) 4(c) Any integer(d) It cannot be oscillatory for any value of nThis question was posed to me in an online quiz.The above asked question is from Periodic and Oscillatory Motions topic in section Oscillations of Physics – Class 11

Answer»

Correct option is (a) 3

To elaborate: For motion to be OSCILLATORY there has to be an equilibrium position TOWARDS which the force is acting throughout the motion.In the expression, F = -kx^n,If n is even, force will ALWAYS act in one direction.If n is odd, force will change direction when x changes direction and will always act towards the origin.Hence, motion will be oscillatory if n is odd.Thus, from the given options 3 is correct.



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