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\(\frac {Cos A}{Sin A}\) = ______(a) Tan A(b) Sin A(c) Cot A(d) Sec AThe question was posed to me in final exam.Asked question is from Trigonometric Ratios topic in division Trigonometry of Mathematics – Class 10

Answer»

Right option is (C) Cot A

For explanation I WOULD say: Sin A = \(\frac {LENGTH \, of \, the \, OPPOSITE \, side}{Length \, of \, the \, hypotenuse}\), Cos A = \(\frac {Length \, of \, the \, adjacent \, side}{Length \, of \, the \, hypotenuse}\)

\(\frac {Cos A}{Sin A} = \frac {Length \, of \, the \, adjacent \, side}{Length \, of \, the \, opposite \, side}\)

= Cot A



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