How many NOT gates are required to implement the Boolean expression: X = AB’C + A’BC?(a) 2(b) 3(c) 4(d) 5I had been asked this question by my school principal while I was bunking the class.I need to ask this question from Fast Adder & Serial Adder topic in portion Arithmetic Circuits of Digital Circuits

How many NOT gates are required to implement the Boolean expression: X

1.	How many NOT gates are required to implement the Boolean expression: X = AB’C + A’BC?(a) 2(b) 3(c) 4(d) 5I had been asked this question by my school principal while I was bunking the class.I need to ask this question from Fast Adder & Serial Adder topic in portion Arithmetic Circuits of Digital Circuits
Answer» The correct answer is (a) 2 The best I can explain: SINCE in the given expression two inputs are complemented. So, we REQUIRE two NOT gate at the input. A NOT gate is a basic gate which ACCEPTS a SINGLE input and produces a single output, which is the inverted version of the input.

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