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If a 10-bit ring counter has an initial state 1101000000, what is the state after the second clock pulse?(a) 1101000000(b) 0011010000(c) 1100000000(d) 0000000000I got this question in an interview for job.I would like to ask this question from Shift Register Counters in division Registers of Digital Circuits

Answer» CORRECT choice is (b) 0011010000

The explanation: After shifting 2-bit we GET the output as 0011010000 (Since two ZEROS are at 1^st position and 2^nd position which came from the last two bits). As in a ring counter, the bits rotate in clockwise direction.


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