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If in a ` A B C , /_A=45^0, /_B=60^0, a n d /_C=75^0`, find the ratio of its sides. |
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Answer» By the sine formula, we have `a:b:c=sinA:sinB:sinC` `=sin45^(@):sin60^(@):sin75^(@)` `=1/sqrt2:sqrt3/2:((sqrt3+1))/(2sqrt2)=2:sqrt6:(sqrt3+1).` |
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