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If `s=sqrt(t^(2)+1)`, then `(d^(2)s)/(dt^(2))` is equal toA. `(1)/(s)`B. `(1)/(s^(2))`C. `(1)/(s^(3))`D. `(1)/(s^(4))` |
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Answer» Correct Answer - C `s=sqrt(t^(2)+1)` `rArr (ds)/(dt)=(t)/(sqrt(t^(2)+1))` `rArr (d^(2)s)/(dt^(2))=(1)/(sqrt((t^(2)+1)^(3)))` `rArr (d^(2)s)/(dt^(2))=(1)/(s^(3))` |
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