1.

If tan θ = \(\frac {3}{4}\) then the value of sinθ is _________(a) \(\frac {3}{5}\)(b) \(\frac {4}{4}\)(c) \(\frac {3}{4}\)(d) \(\frac {-3}{5}\)This question was posed to me during an interview.My question is from Trigonometric Ratios topic in portion Trigonometry of Mathematics – Class 10

Answer»

Correct option is (a) \(\frac {3}{5}\)

The best I can explain: tanθ = \(\frac {BC}{AC} = \frac {3}{4} = \frac {3k}{4k}\)

HENCE, BC = 3k, AC = 4k

Using Pythagoras theorem

AB^2 = AC^2 + BC^2

AB^2 = 4k^2 + 3k^2

AB = 5k

sinθ = \(\frac {BC}{AB} = \frac {3k}{5k} = \frac {3}{5}\)



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