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If | x | < 1, then the coefficient of xn in (1 + 2x + 3x2 + 4x3 + ....)1/2 is(a) 1 (b) – n (c) n (d) n + 1 |
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Answer» Answer : (a) 1 (1 + 2x + 3x2 + 4x3 + ....)1/2 = [(1 – x) –2]1/2 = (1 – x) –1 = 1 + x + x2 + x3 + ..... ⇒ coefficient of each term = 1 ⇒ coefficient of xn = 1. |
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