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If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2 ? |
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Answer» Given: x = asin θ and y = bcos θ ⇒ x2 = a2 sin2 θ and y2 = b2 cos2θ ………(i) To find: b2x2 + a2y2 Consider b2x2 + a2y2 = b2a2 sin2θ +a2b2cos2θ = a2 b2 (sin2θ + cos2θ) = a2 b2 (1) [∵ sin2 θ + cos2θ = 1] = a2 b2 |
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