1.

If x = a sin θ and y = b cos θ, what is the value of b2x2 + a2y2 ?

Answer»

Given: x = asin θ and y = bcos θ 

⇒ x2 = a2 sin2 θ and y2 = b2 cos2θ ………(i) 

To find: b2x2 + a2y2 

Consider b2x2 + a2y2 = b2a2 sin2θ +a2b2cos2θ 

= a2 b2 (sin2θ + cos2θ) 

= a2 b2 (1) [∵ sin2 θ + cos2θ = 1] 

= a2 b2



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