1.

If y = |logex|, find \(\frac{d^2y}{dx^2}\).

Answer»

Given:

y = |loge x| \(\forall x>0\)

y = loge x

\(\frac{dy}{dx}=\frac{1}{x}=x^{-1}\)

\(\frac{d^2y}{dx^2}=(-1)x^{-2}\)



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