If `y=sin(ax+b)`, then what is `(d^(2)y)/(dx^(2))` at `x=-(b)/(a)`, where a, be are constants and `a ne 0`?

If `y=sin(ax+b)`, then what is `(d^(2)y)/(dx^(2))` at `x=-(b)/(a)`, wh

1.	If `y=sin(ax+b)`, then what is `(d^(2)y)/(dx^(2))` at `x=-(b)/(a)`, where a, be are constants and `a ne 0`?
Answer» Correct Answer - A Let y = sin(ax + b) `rArr (dy)/(dx) = a cos(ax + b)` `rArr (d^(2)y)/(dx^(2))= -a^(2) sin(ax+b)` Now, `(d^(2)y)/(dx^(2)) "at x" = -(b)/(a)` is `-a^(2)sin(a(-(b)/(a))+b)=-a^(2) sin 0 = 0`