If z = 1 – cos θ + i sin θ, then |z| = A. 2sin \(\frac{θ}{2}\)B

1.	If z = 1 – cos θ + i sin θ, then \|z\| = A. 2sin \(\frac{θ}{2}\)B. 2cos \(\frac{θ}{2}\)C. \(2\|sin\frac{θ}{2}\|\)D. \(2\|cos\frac{θ}{2}\|\)
Answer» \|z\| = \(\sqrt{(1-cosθ)^2 + (sinθ)^2}\) =\(\sqrt{2-2cosθ}\) = \(2\|sin\frac{θ}{2}\|\)

If z = 1 – cos θ + i sin θ, then |z| = A. 2sin \(\frac{θ}{2}\)B. 2cos \(\frac{θ}{2}\)C. \(2|sin\frac{θ}{2}|\)D. \(2|cos\frac{θ}{2}|\)

Answer»

|z| = \(\sqrt{(1-cosθ)^2 + (sinθ)^2}\)

=\(\sqrt{2-2cosθ}\)

= \(2|sin\frac{θ}{2}|\)