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If |z – 5i| = |z + 5i|, then find the locus of z. |
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Answer» z = a + ib |a+ib-5i| = |a+ib+5i| |a+ib-5i|2 = |a+ib+5i|2 |a +i(b-5)|2 = |a + i(b+5)|2 a2+(b-5)2 = a2+(b+5)2 a2+b2+25-10b = a2+b2+25+10b 20b = 0 b = 0 b is a imaginary part of z Im(z) = \(\frac{z-\bar z}{2}\) = y = 0 Im (z) = 0 So, the locus point is real axis |
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